Introduction to help with statistics class online study:

Statistical means that the learning about the mean, mode, median and also range. The statistics are the process of the design of the survey and also the experiments. Statistics has the quantities find for the data. Statistics include the collection, analysis and also the interpretation. Statistics is used to find the population analysis. Statistics provides the collection, analysis of the data. Online provides the connectivity between the students and also the tutors.       

  

Examples for the help with statistics class online study:

 

Example 1 to the help with statistics class online study:   

Evaluate the mean, mode and the median for the data 7024, 7026, 7021, 7026, 7023.

Solution:

The given data is 7024, 7026, 7021, 7026, 7023.

The formula used to resolve mean = `(c1+c2+c3+. . . . . .+c n)/n`   

Step 1: Mean =` (7024+7026+7021+7026+7023)/5`

Step 2: Mean = `35120/5`

Step 3: Mean = 7024    

Step 4: 7021, 7023, 7024, 7026, 7026. (Data in the ascending order)  

Step 5: Median = 7024

Step 6: Mode = 7026 (Frequently placed data)

The mean value for the data 7024, 7026, 7021, 7026, 7023 is 7024. The median for the given data is 7024 and mode is 7026. 

 Example 2 to the help with statistics class online study:  

Estimate the mean, mode and median for the data 5219, 5214, 5215, 5214, 5217. 

Solution: 

The given data is 5219, 5214, 5215, 5214, 5217. 

The formula used to resolve mean = `(c1+c2+c3+. . . . . .+c n)/n`

Step 1: Mean =` (5219+5214+5215+5214+5217)/5`

Step 2: Mean = `26079/5`

Step 3: Mean = 5215.8

Step 4: 5214, 5214, 5215, 5217, 5219. (Data in the ascending order)   

Step 5: Median = 5215

Step 6: Mode = 5214 (Frequently placed data)

The mean value for the data 5219, 5214, 5215, 5214, 5217 is 5215.8. The median for the given data is 5215 and the mode is 5214.  

Example 3 to the help with statistics class online study:  

Determine the mean, mode and median for the given data 9435, 9439, 9433, 9437, 9433, 9432. 

Solution:    

The given data is 9435, 9439, 9433, 9437, 9433, 9432.  

The formula used to resolve mean = `(c1+c2+c3+. . . . . .+c n)/n`

Step 1: Mean =` (9435+9439+9433+9437+9433+9432)/6`

Step 2: Mean = `56609/6`

Step 3: Mean = 9434.8

Step 4: 9432, 9433, 9433, 9435, 9437, 9439. (Data in the ascending order)   

Step 5: Median = `(9433+9435)/2` = 9434

Step 6: Mode = 9433 (Frequently placed data)

The mean for the data 9435, 9439, 9433, 9437, 9433, 9432 is 9434.8. The median for the given data is 9434 and the mode is 9433.

    

Practice problem for the help with statistics class online study:

 

  • Predict the mean, mode and median for the data 1621, 1626, 1623, 1625, 1626.  

Answer: mean = 1624.2, median = 1625, mode = 1626.

  • Resolve the mean, mode and median for the data 4869, 4864, 4860, 4865, 4868, 4863, 4867, 4863.

Answer: mean = 4864.875, median = 4864.5, mode = 4863.