Tutorials help people study new additional skills by using a stepbystep process but make sure the user is following beside and understanding. Statistics is the suitable science of
creating ordered use of arithmetic data between the groups of individuals. It deals with all features of this, jointly with not only the group, study and understanding of such data, but also the
planning of the collection of data.Now we will see the advanced statistics examples.
The ages of the students are 8,12,13,16,21. Find the standard deviation, mean and median of the students.
Solution:
Standard Deviation
The given numbers are 8,12,13,16,21.
Standard deviation formula is as follows,
S=`sqrt((sum(ax)^2)/(n1))`
Now find the mean value. (Because solve the standard deviation).
X=`(8+12+13+16+21)/5`
=`70/5`
X=14.
a 
ax 
(ax)^{2} 
8 
6 
36 
12 
2 
4 
13 
1 
1 
16 
2 
4 
21 
7 
49 
Total 

94 
S=`sqrt((94)/(51))`
=`sqrt(23.5)`
S=4.84.
Mean
The ages of students is 8,12,13,16,21.
Average of the digits is a mean. Can calculate the average with the help of given digits.
Sum of the given numbers = 8+12+13+16+21
= 70.
Total value 70is divided by5 (5 is the total numbers) = `70/5`
= 14.
Median
Center element of the given series is a median.
The given numbers are 8,12,13,16,21.
The center value of the above sequence is 13.
Median=13.
In a Maths subject, the students got the following marks. Find the mean, mode and range of the marks.
54,58,64,68,75.
Solution:
The given numbers are 54,58,64,68,75.
Standard deviation formula is as follows,
S=`sqrt((sum(ax)^2)/(n1))`
Now find the mean value. (Because solve the standard deviation).
X=`(54+58+64+68+75)/5`
=`319/5`
X=63.8.
a 
ax 
(ax)^{2} 
54 
9.8 
96.04 
58 
5.8 
33.64 
64 
0.2 
0.04 
68 
4.2 
17.64 
75 
11.2 
125.44 
Total 

272.8 
S=`sqrt((272.8)/(51))`
=`sqrt(68.2)`
S=8.25.
Mode
The replica value is the mode.
So mode=Null (Since there is no replica value).
Range
Subtract the least value from top value.
Range =7554
=21.
These are the examples are used to understand about advanced statistics tutorial.