Introduction for shape of quadrilateral:

In this article we see about the shape of a quadrilateral, a quadrilateral is a polygon figure with 4 sides. Square, rectangle, rhombus, parallelogram, trapezoid and kite are the shape of quadrilaterals. We can find area and volume of all the shape of quadrilaterals. Area of quadrilateral is measured in square units and volume is measured in cubic units.

 

Shape of quadrilateral:

 

Let us see some shapes of quadrilateral

Square: All the 4 sides are equal; all the angles are right angles.

                                              Shape of square

Rectangle: Both opposite sides are equal, all the angles are right angles.

                                               Shape of rectangle

Rhombus: All the 4 sides are equal; opposite angles are equal.

                                                Shape of rhombus

Parallelogram: Both opposite sides are equal, opposite angles are equal.

                                              Shape of parallelogram

Trapezoid: One pair of opposite sides is parallel and the base angles are equal in measure.

                                              Shape of trapeziod

Kite: Two pairs of adjacent sides are equal; angles between the two pairs of equal sides are equal.

                                              Shape of kite

To find area for quadrilateral shape:

Area of square = a2 (a =side)

Area of rectangle = lb (l = length, b = breath)

Area of rhombus = ba (b = base, a = altitude)

Area of parallelogram = al (a = altitude, l = length)

Area of trapezoid = ½ (b1 + b2)h (h = height, b1 = base 1, b2 = base 2)

Area of kite = Area triangle of 1 + Area of triangle of 2

Area of triangle = ½ bh (b = base, h = height)

 

Example problem for shape of quadrilateral

 

Example 1:

Find area of the shape parallelogram, whose length is 7m and altitude is 6m

Solution:

Given: a = 6m, l = 7m

 Area of parallelogram  = a × l

                                           = 6 × 7

                                           = 42m2

Example 2:

Find area of the kite ABCD where h1 = 12cm, h2 = 10cm and base = 6cm.

Solution:

Given: h1 = 12cm, h2 = 10cm and b = 6cm.

Area of the kite = Area triangle of 1 + Area of triangle of 2

Area of triangle ABD = 1/2 × b × h

                                      = 1/2 × 6 × 12

                                      = 36cm2

Area of triangle BCD = 1/2 × 6 × 10

                                      = 1/2 × 60

                                      = 30cm2

Area of kite shape = 36 + 30

                                  = 66cm2